Class 12 Maharashtra State Board
Find the pressure 200 m below the surface of the ocean if pressure on the free surface of liquid is one atmosphere. (Density of sea water = 1060 kg/m³ )
As per the given question we can list some data as
height h=200m
density ρ = 1060 kg/m³
Atmospheric pressure P₀ = 1.013 x 10⁵ N/m²
acceleration due to gravity g = 9.8m/s²
To find, Pressure below 200m P = ?
Solution -
Absolute pressure , P = P₀ + ρgh
P = 1.013 x 10⁵ + (1060 x 9.8 x 200)
P = 1.013 x 10⁵ + 20.776 x 10⁵
P = 21.789 x 10⁵ Pa
P = 2.1789 x 10⁶ Pa
P = 2.1789 MPa