An ideal gas is taken through an isothermal process. If it does 2000 J of work on its environment, how much heat is added to it?

Given data from the question can be listed as 

dW = 2000J

To find , Heat added dQ = ?

Solution - 

From first law of thermodynamics we can write

dQ = dU + dW

As per the given question the gas is taken through isothermal process, i.e the change in internal energy should be ZERO i.e dU =0

therefore, dQ = 0 + dW 

dQ = dW = 2000J