Doors of a dam are 20m below the surface of water in the dam. If one door is opened what will be the speed of the water that flows out of the door ?
The given can be listed as, h= 20m g = 9.8m/s² To find, v = ? Solution -…
Given data here are, velocity , v= 205 km/ hr = 205 x 1000/ 3600 m/s v = 2050/36 m/s…
Given data here are, velocity , v= 246.2 km/ hr = 246.2 x 1000/ 3600 m/s v = 2462/36 m…
Given data here are, velocity , v= 161.3 km/ hr = 161.3 x 1000/ 3600 m/s v = 1613/36 …
Given data here are mass, m= 420g = 0.420 kg velocity , v= 20m/s therefore momentum …
As per the given question let us find what is given over here Let the distance covered…
As per the given situation in the question above, we have distance = 10km time = 15 …
The given can be listed as, h= 20m g = 9.8m/s² To find, v = ? Solution -…
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