What is the angular speed of a the tip of the minute hand of a clock

Manoj Jaiswar ( PMJ Sir )
by Manoj Jaiswar ( PMJ Sir ) February 19, 2022

 A minute hand completes one revolution (2𝞹 radians) in one hour 

so its angular speed is = angular displacement / time

= (2𝞹 / 3,600) rad/s

= (𝞹 / 1,800) rad/s

= 3.142 / 1800 rad/s

= 0.001745 rad/s

Manoj Jaiswar ( PMJ Sir )

Posted by Manoj Jaiswar ( PMJ Sir )